A = \sqrt21(21 - 13)(21 - 14)(21 - 15) = \sqrt21 \cdot 8 \cdot 7 \cdot 6

Unlock the Power of Square Roots: Solve A = √[21(21 – 13)(21 – 14)(21 – 15)] with Confidence

Mathematics often presents challenges in the form of elegant algebraic expressions—like the powerful cancellation technique behind the square root equation:
A = √[21(21 – 13)(21 – 14)(21 – 15)]

At first glance, this may look like a standard expression, but it reveals a deeper mathematical insight involving factoring, simplification, and clever substitution. Let’s unpack this expression step-by-step to uncover how it simplifies effortlessly—and why it matters.

Understanding the Context

Breaking Down the Expression: A = √[21(21 – 13)(21 – 14)(21 – 15)]

Start by calculating each term inside the parentheses:

21 – 13 = 8
21 – 14 = 7
21 – 15 = 6

Solved square root multiplication: Basic Simplify: 21⋅3 | Chegg.com

Image Gallery

$SOLVED:Evaluate \int_{1}^{3} \frac{d x}{\sqrt{x^{4}+4 x^{2}+3}} \cdot ...$

$inequality - $\frac{1}{15}$

$If \( \frac{1}{2 \cdot 3^{10}}+\frac{2}{2^{2} \cdot 3^{9}}+\frac{3}{2 ...$

Solved: Resolvendo a expressão abaixo, marque a alternativa correta: 5 ...

Key Insights

So the expression becomes:
A = √[21 × 8 × 7 × 6]

Instead of leaving it as a product of four numbers, we simplify by reordering and grouping factors:

A = √(21 × 8 × 7 × 6) = √[21 × 7 × 8 × 6]

Notice the pairing: 21 and 7 are multiples, and 8 and 6 share common structure. This sets the stage for factoring to reveal perfect squares—the key to simplifying square roots.

🔗 Related Articles You Might Like:

📰 Stickman Battle Game 📰 Stickman Battle Games 📰 Stickman Battles 📰 Hacked By A Robot Unicorn The Scariest Attack Game Ever Released 4965573 📰 The Oh Surprising Reason Ellie May Have Killed Abby Is This Final 7952724 📰 Skateboard Games Pc 6270342 📰 Can I Encash A Check In Any Bank 1571221 📰 Geriatric Investors This Annuity Rmd Breakdown Could Save You Thousands 465309 📰 Cinepolis In Vista The Hidden Reasons Moviegoers Are Going Wild 7463213 📰 The Center Of The Hyperbola Is H K 3 2 5611772 📰 The Shocking Truth Behind Streamaus Unbelievable Streamno One Anticipated It 620207 📰 Builds Thesaurus 339937 📰 Banks And Business Loans 7758245 📰 Video Editor Camtasia 1209558 📰 Aloft In Mount Laurel 1192389 📰 All Inclusive Cancun With Flight 4851927 📰 Time To Fill The Tank Is Frac1Frac512 Frac125 24 Hours 2659832 📰 How To Schedule A Meeting In Outlook 9636616

Final Thoughts

Step 1: Factor and Rearrange

Let’s factor each number into primes:

21 = 3 × 7
8 = 2³
7 = 7
6 = 2 × 3

Putting it all together:
A = √[(3 × 7) × (2³) × (7) × (2 × 3)]

Now combine like terms:

2³ × 2 = 2⁴ (since 2³ × 2 = 2⁴ = 16)
3 × 3 = 3²
7 × 7 = 7²

So the radicand becomes:
A = √(2⁴ × 3² × 7²)

Step 2: Extract Perfect Squares

Using the property √(a×b) = √a × √b, we separate each squared term:

A = √(2⁴) × √(3²) × √(7²)