A rectangular prism has a volume of 360 cubic meters. Its length is twice its width, and its height is 3 meters. What is the width of the prism in meters? - IQnection
Write the article as informational and trend-based content, prioritizing curiosity, neutrality, and user education over promotion.
Write the article as informational and trend-based content, prioritizing curiosity, neutrality, and user education over promotion.
Discover Reading Hook:
Curious about the math behind everyday shapes? A rectangular prism measures 360 cubic meters of space, standing 3 meters tall with length twice its width—key details shaping engineering, packaging, and design. For curious minds, solving this simple volume puzzle offers more than a number: it reveals how finite space becomes functional design.
Understanding the Context
Why A rectangular prism has a volume of 360 cubic meters. Its length is twice its width, and its height is 3 meters. What is the width of the prism in meters? Is Gaining Traction in US Digital Conversations
Across U.S. tech forums, educational platforms, and home improvement blogs, a quiet inquiry is rising: “A rectangular prism has a volume of 360 cubic meters. Its length is twice its width, and its height is 3 meters. What is the width of the prism in meters?” This question reflects growing interest in spatial math—applications that blend practicality with clarity. Users aren’t just solving equations—they’re building understanding of real-world geometry driving modern design and efficiency.
The complexity lies in balancing three variables: width, length (twice the width), and fixed height. Together, these define how much space a container, model, or structure can hold—information critical in construction, logistics, and industrial planning.
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How A rectangular prism has a volume of 360 cubic meters. Its length is twice its width, and its height is 3 meters. What is the width of the prism in meters?
A rectangular prism’s volume is calculated using the formula:
Volume = length × width × height
Given:
- Volume = 360 m³
- Height = 3 meters
- Length = 2 × Width (let width = w, so length = 2w)
Substitute into the formula:
360 = (2w) × w × 3
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Simplify:
360 = 6w²
Now solve for w:
w² = 360 ÷ 6 = 60
w = √60 = √(4 × 15) = 2√15 meters
Approximately, √15 ≈ 3.873, so w ≈ 7.75 meters—exact value remains 2√15 in precise calculation.
This calculation reveals that despite the length
