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📅 May 3, 2026 👤 scraface

May 03, 2026

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Then $y = 2\left(rac{8}{5}
ight) + 1 = rac{16}{5} + rac{5}{5} = rac{21}{5}$.
Thus, the closest point is $\left(rac{8}{5}, rac{21}{5}
oxed{\left( \dfrac{8}{5},\ \dfrac{21}{5}
Question: Find the vector $\mathbf{v}$ that satisfies $\mathbf{v} ime...
angle$ and $\mathbf{b} = \langle 4, 5, 6
Solution: The vector equation $\mathbf{v} imes \mathbf{a} = \mathbf{b...
\mathbf{a} \cdot \mathbf{b} = 1(4) + 2(5) + 3(6) = 4 + 10 + 18 = 32
Since the dot product is not zero, there is **no** vector $\mathbf{v}$...
oxed{ ext{No such vector } \mathbf{v} ext{ exists}}

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