Solution: The area of a circular sector is \( A = \frac{\theta}{360} \pi r^2 \). Original area: \( \frac{90}{360} \pi (12)^2 = 36\pi \). New radius: \( 12 + 4 = 16 \) meters. New area: \( \frac{90}{360} \pi (16)^2 = 64\pi \). The increase is \( 64\pi - 36\pi = 28\pi \). \boxed{28\pi}

Sat, 02 May 2026 17:30:40 +0000

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