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📅 May 4, 2026 👤 scraface

May 04, 2026

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h = \sqrt{13^2 - 5^2} = \sqrt{169 - 25} = \sqrt{144} = 12 \text{ cm}
The area of the original triangle is:
A_1 = \frac{1}{2} \times 10 \times 12 = 60 \text{ cm}^2
Next, increase the base to 12 cm and find the new height \( h' \) usin...
h' = \sqrt{13^2 - \left(\frac{12}{2}\right)^2} = \sqrt{169 - 36} = \sq...
The area of the new triangle is:
A_2 = \frac{1}{2} \times 12 \times \sqrt{133} = 6\sqrt{133} \text{ cm}...
Calculate the change in area:
\Delta A = A_2 - A_1 = 6\sqrt{133} - 60
Thus, the change in the area of the triangle is:

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