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squamous cell carcinoma in situ - IQnection

📅 May 4, 2026 👤 scraface

May 04, 2026

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📌 Divide the entire equation by 88:

📌 \frac{9(x - 3)^2}{88} - \frac{16(y - 2)^2}{88} = 1

📌 Simplifies to:

📌 \frac{(x - 3)^2}{\frac{88}{9}} - \frac{(y - 2)^2}{\frac{88}{16}} = 1

📌 The center of the hyperbola is \((h, k) = (3, 2)\).

📌 Therefore, the center of the hyperbola is \(\boxed{(3, 2)}\).

📌 A science policy analyst is evaluating a proposal involving the sum of a series for technological forecasting. Compute \(\sum_{n=1}^{50} \frac{1}{n(n+1)}\).

📌 The series \(\sum_{n=1}^{50} \frac{1}{n(n+1)}\) is a telescoping series. We simplify each term using partial fractions:

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