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the fall of the berlin wall - IQnection

📅 May 2, 2026 👤 scraface

May 02, 2026

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📌 $\sin(2 \cdot 90^\circ) = \sin(180^\circ) = 0$, $\cos(90^\circ) = 0$ â satisfies.

📌 $\sin(270^\circ) = -1$, $\cos(270^\circ) = 0$ â $-1 = 0$? No â Not valid.

📌 So only solutions where $\cos z = 0$ and $\sin z = 1/2$, but $\cos z = 0$ at $z = 90^\circ, 270^\circ$, but $\sin(270^\circ) = -1

📌 Only valid are $z = 30^\circ$ and $z = 150^\circ$.

📌 At $z = 150^\circ$: $\sin(300^\circ) = \sin(-60^\circ) = -\sqrt{3}/2$, $\cos(150^\circ) = -\sqrt{3}/2$ â equal.

📌 So all three? Wait: $\sin(2z) = \cos z$:

📌 $z = 30^\circ$: $\sin(60^\circ) = \sqrt{3}/2$, $\cos(30^\circ) = \sqrt{3}/2$ â OK.

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