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📅 May 4, 2026 👤 scraface

May 04, 2026

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📌 Pour trouver la largeur, dÃ©signons la largeur par \( w \). Alors la longueur est \( 3w \). Le pÃ©rimÃ¨tre d'un rectangle est donnÃ© par la formule :

📌 \[ P = 2( ext{longueur} + ext{largeur}) \]

📌 Substituons les valeurs donnÃ©es :

📌 \[ 64 = 2(3w + w) \]

📌 Simplifions l'Ã©quation :

📌 \[ 64 = 2(4w) \]

📌 \[ 64 = 8w \]

📌 Divisons les deux cÃ´tÃ©s par 8 :

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\[ (4 - \lambda)(3 - \lambda) - 2 = 0 \]
\[ (12 - 4\lambda - 3\lambda + \lambda^2) - 2 = 0 \]
\[ \lambda^2 - 7\lambda + 10 = 0 \]
\[ \lambda = rac{7 \pm \sqrt{(-7)^2 - 4 \cdot 1 \cdot 10}}{2 \cdot 1}...
\[ \lambda = rac{7 \pm \sqrt{49 - 40}}{2} \]
\[ \lambda = rac{7 \pm \sqrt{9}}{2} \]
\[ \lambda = rac{7 \pm 3}{2} \]
The eigenvalues are:
\( \lambda = rac{10}{2} = 5 \)
\( \lambda = rac{4}{2} = 2 \)

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