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📅 May 5, 2026 👤 scraface

May 05, 2026

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📌 ENIAC: 20 digits × 10 registers × (4 bits / 8 bits per byte) × 1 byte per 4 bits = 20 × 10 = 200 bytes

📌 Improved: 16 × 2 = 32 bytes

📌 But ENIAC occupies 200 bytes

📌 Yet the difference is not required.

📌 Re-read: how many total bytes does the ENIAC register memory occupy — pure count from specs:

📌 digits × 10 registers = 200 digit-equivalents, but memory stored in bytes.

📌 Assume 1 digit = 1/8 byte → 20 digits = 20/8 = 2.5 bytes per register

📌 × 2.5 = <<10*2.5=25>>25 bytes

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